EC8392 DE 2marks 16marks, Digital Electronics Question Bank, DE Short Answers


EC8392 DE 2marks

Anna University Regulation 2017 EC8392 DE 2marks & 16marks for all 5 units are provided below. EC8392 DE Short answers, Question Bank for Digital Electronics Engineering are listed down for students to make perfect utilization and score maximum marks with our study materials.


UNIT-I 2-marks 

3. What are Don’t care terms?
In some logic circuits certain input conditions never occur, therefore the corresponding output never appears. In such cases the output level is not defined, it can be either high or low. These output levels are indicated by ‘X’ or ‘d’ in the truth tables and are called don’t care conditions or incompletely specified functions.

4. Apply De-Morgan’s theorem to [ (A+B) + C ] ′.
Given [(A+B)+C] ′ = (A+B) ′.C′
= (A′.B′).C′
[(A+B)+C] ′ = A′B′C′

5. Convert 0.35 to equivalent hexadecimal number.
Given (0.35)10 =0.35 x 16=5.60
=0.60 x 16=9.60
=0.60 x 16=9.60
(0.35)10 = (0.599)16

6. Convert Y=A+BC′+AB+A′BC into canonical form.
Given Y=A+BC′+AB+A′BC

7. Define ‘min term’ and ‘max term’.
A product term containing all the variables of the function in either complemented or uncomplemented form is called a min term.
A sum term containing all the variables of the function in either complemented or uncomplemented form is called a max term.

8. Prove that the logical sum of all min terms of a Boolean function of 2 variables is 1.

Consider two variables as A and B. For two variables A and B minterms are:
A′B′,A′B,AB′,AB. The logical sum of these minterms are given by
F= A′B′+A′B+AB′+AB
= A′(B′+B)+A(B′+B) (B′+B=1)
= A′(1)+A(1) (A′+A=1)
Hence it is to be proved

EC8392 DE All Units 2marks & 16marks – Download Here

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EC8392 Digital Electronics Engineering question bank free download

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EC8392 2marks, DE Unit wise short answers – 3rd Semester


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